Solve 30+(10-9)div(2*10-9-3)*5

$$30+(10-9) \div (2 \times 10-9-3) \times 5$$

Evaluate

$$\frac{245}{8}=30.625$$

Solution Steps

Subtract 9 from 10 to get 1.

$$30+\frac{1}{2\times 10-9-3}\times 5$$

Multiply 2 and 10 to get 20.

$$30+\frac{1}{20-9-3}\times 5$$

Subtract 9 from 20 to get 11.

$$30+\frac{1}{11-3}\times 5$$

Subtract 3 from 11 to get 8.

$$30+\frac{1}{8}\times 5$$

Multiply \frac{1}{8} and 5 to get \frac{5}{8}.

$$30+\frac{5}{8}$$

Convert 30 to fraction \frac{240}{8}.

$$\frac{240}{8}+\frac{5}{8}$$

Since \frac{240}{8} and \frac{5}{8} have the same denominator, add them by adding their numerators.

$$\frac{240+5}{8}$$

Add 240 and 5 to get 245.

$$\frac{245}{8}$$

Factor

$$\frac{5 \cdot 7 ^ {2}}{2 ^ {3}} = 30\frac{5}{8} = 30.625$$