Solve 30+6^2-9*2^2-sqrt{9}+9-9div3

$$30+ { 6 }^{ 2 } -9 \times { 2 }^{ 2 } - \sqrt{ 9 } +9-9 \div 3$$

Evaluate

$$33$$

Solution Steps

Calculate 6 to the power of 2 and get 36.

$$30+36-9\times 2^{2}-\sqrt{9}+9-\frac{9}{3}$$

Add 30 and 36 to get 66.

$$66-9\times 2^{2}-\sqrt{9}+9-\frac{9}{3}$$

Calculate 2 to the power of 2 and get 4.

$$66-9\times 4-\sqrt{9}+9-\frac{9}{3}$$

Multiply 9 and 4 to get 36.

$$66-36-\sqrt{9}+9-\frac{9}{3}$$

Subtract 36 from 66 to get 30.

$$30-\sqrt{9}+9-\frac{9}{3}$$

Calculate the square root of 9 and get 3.

$$30-3+9-\frac{9}{3}$$

Subtract 3 from 30 to get 27.

$$27+9-\frac{9}{3}$$

Add 27 and 9 to get 36.

$$36-\frac{9}{3}$$

Divide 9 by 3 to get 3.

$$36-3$$

Subtract 3 from 36 to get 33.

$$33$$

Factor

$$3\times 11$$