Solve 30x^2-60x=0

$$30 x ^ { 2 } - 60 x = 0$$

Solve for x

$$x=2$$

$$x=0$$

Steps Using Factoring

Factor out x.

$$x\left(30x-60\right)=0$$

To find equation solutions, solve x=0 and 30x-60=0.

$$x=0 x=2$$

Steps Using the Quadratic Formula

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$30x^{2}-60x=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 30 for a, -60 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-60\right)±\sqrt{\left(-60\right)^{2}}}{2\times 30}$$

Take the square root of \left(-60\right)^{2}.

$$x=\frac{-\left(-60\right)±60}{2\times 30}$$

The opposite of -60 is 60.

$$x=\frac{60±60}{2\times 30}$$

Multiply 2 times 30.

$$x=\frac{60±60}{60}$$

Now solve the equation x=\frac{60±60}{60} when ± is plus. Add 60 to 60.

$$x=\frac{120}{60}$$

Divide 120 by 60.

$$x=2$$

Now solve the equation x=\frac{60±60}{60} when ± is minus. Subtract 60 from 60.

$$x=\frac{0}{60}$$

Divide 0 by 60.

$$x=0$$

The equation is now solved.

$$x=2 x=0$$

Steps for Completing the Square

Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.

$$30x^{2}-60x=0$$

Divide both sides by 30.

$$\frac{30x^{2}-60x}{30}=\frac{0}{30}$$

Dividing by 30 undoes the multiplication by 30.

$$x^{2}+\left(-\frac{60}{30}\right)x=\frac{0}{30}$$

Divide -60 by 30.

$$x^{2}-2x=\frac{0}{30}$$

Divide 0 by 30.

$$x^{2}-2x=0$$

Divide -2, the coefficient of the x term, by 2 to get -1. Then add the square of -1 to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}-2x+1=1$$

Factor x^{2}-2x+1. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-1\right)^{2}=1$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x-1\right)^{2}}=\sqrt{1}$$

Simplify.

$$x-1=1 x-1=-1$$

Add 1 to both sides of the equation.

$$x=2 x=0$$