Solve for x
x=-\frac{4y}{3}+\frac{7}{30}
Solve for y
y=-\frac{3x}{4}+\frac{7}{40}
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30x=7-40y
Subtract 40y from both sides.
\frac{30x}{30}=\frac{7-40y}{30}
Divide both sides by 30.
x=\frac{7-40y}{30}
Dividing by 30 undoes the multiplication by 30.
x=-\frac{4y}{3}+\frac{7}{30}
Divide 7-40y by 30.
40y=7-30x
Subtract 30x from both sides.
\frac{40y}{40}=\frac{7-30x}{40}
Divide both sides by 40.
y=\frac{7-30x}{40}
Dividing by 40 undoes the multiplication by 40.
y=-\frac{3x}{4}+\frac{7}{40}
Divide 7-30x by 40.
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