Solve 30b+53geq18b-83

$$30 b + 53 \geq 18 b - 83$$

Solve for b

$$b\geq -\frac{34}{3}$$

Solution Steps

Subtract 18b from both sides.

$$30b+53-18b\geq -83$$

Combine 30b and -18b to get 12b.

$$12b+53\geq -83$$

Subtract 53 from both sides.

$$12b\geq -83-53$$

Subtract 53 from -83 to get -136.

$$12b\geq -136$$

Divide both sides by 12. Since 12 is positive, the inequality direction remains the same.

$$b\geq \frac{-136}{12}$$

Reduce the fraction \frac{-136}{12} to lowest terms by extracting and canceling out 4.

$$b\geq -\frac{34}{3}$$