Solve 30b+53>18b-83

$$30 b + 53 > 18 b - 83$$

Solve for b

$$b>-\frac{34}{3}$$

Solution Steps

Subtract 18b from both sides.

$$30b+53-18b>-83$$

Combine 30b and -18b to get 12b.

$$12b+53>-83$$

Subtract 53 from both sides.

$$12b>-83-53$$

Subtract 53 from -83 to get -136.

$$12b>-136$$

Divide both sides by 12. Since 12 is positive, the inequality direction remains the same.

$$b>\frac{-136}{12}$$

Reduce the fraction \frac{-136}{12} to lowest terms by extracting and canceling out 4.

$$b>-\frac{34}{3}$$