Solve 30(-5/3y+68/3)+40y=1240

$$30 ( - \frac { 5 } { 3 } y + \frac { 68 } { 3 } ) + 40 y = 1240$$

Solve for y

$$y=-56$$

Steps for Solving Linear Equation

Use the distributive property to multiply 30 by -\frac{5}{3}y+\frac{68}{3}.

$$30\left(-\frac{5}{3}\right)y+30\times \frac{68}{3}+40y=1240$$

Express 30\left(-\frac{5}{3}\right) as a single fraction.

$$\frac{30\left(-5\right)}{3}y+30\times \frac{68}{3}+40y=1240$$

Multiply 30 and -5 to get -150.

$$\frac{-150}{3}y+30\times \frac{68}{3}+40y=1240$$

Divide -150 by 3 to get -50.

$$-50y+30\times \frac{68}{3}+40y=1240$$

Express 30\times \frac{68}{3} as a single fraction.

$$-50y+\frac{30\times 68}{3}+40y=1240$$

Multiply 30 and 68 to get 2040.

$$-50y+\frac{2040}{3}+40y=1240$$

Divide 2040 by 3 to get 680.

$$-50y+680+40y=1240$$

Combine -50y and 40y to get -10y.

$$-10y+680=1240$$

Subtract 680 from both sides.

$$-10y=1240-680$$

Subtract 680 from 1240 to get 560.

$$-10y=560$$

Divide both sides by -10.

$$y=\frac{560}{-10}$$

Divide 560 by -10 to get -56.

$$y=-56$$