Solve 30:(3*7+11)+2^3=

$$30 : ( 3 \cdot 7 + 11 ) + 2 ^ { 3 } =$$

Evaluate

$$\frac{143}{16}=8.9375$$

Solution Steps

Multiply 3 and 7 to get 21.

$$\frac{30}{21+11}+2^{3}$$

Add 21 and 11 to get 32.

$$\frac{30}{32}+2^{3}$$

Reduce the fraction \frac{30}{32} to lowest terms by extracting and canceling out 2.

$$\frac{15}{16}+2^{3}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{15}{16}+8$$

Convert 8 to fraction \frac{128}{16}.

$$\frac{15}{16}+\frac{128}{16}$$

Since \frac{15}{16} and \frac{128}{16} have the same denominator, add them by adding their numerators.

$$\frac{15+128}{16}$$

Add 15 and 128 to get 143.

$$\frac{143}{16}$$

Factor

$$\frac{11 \cdot 13}{2 ^ {4}} = 8\frac{15}{16} = 8.9375$$