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3.9248x^{2}+0.724x-0.6087=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-0.724±\sqrt{0.724^{2}-4\times 3.9248\left(-0.6087\right)}}{2\times 3.9248}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 3.9248 for a, 0.724 for b, and -0.6087 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-0.724±\sqrt{0.524176-4\times 3.9248\left(-0.6087\right)}}{2\times 3.9248}
Square 0.724 by squaring both the numerator and the denominator of the fraction.
x=\frac{-0.724±\sqrt{0.524176-15.6992\left(-0.6087\right)}}{2\times 3.9248}
Multiply -4 times 3.9248.
x=\frac{-0.724±\sqrt{0.524176+9.55610304}}{2\times 3.9248}
Multiply -15.6992 times -0.6087 by multiplying numerator times numerator and denominator times denominator. Then reduce the fraction to lowest terms if possible.
x=\frac{-0.724±\sqrt{10.08027904}}{2\times 3.9248}
Add 0.524176 to 9.55610304 by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
x=\frac{-0.724±\frac{\sqrt{3937609}}{625}}{2\times 3.9248}
Take the square root of 10.08027904.
x=\frac{-0.724±\frac{\sqrt{3937609}}{625}}{7.8496}
Multiply 2 times 3.9248.
x=\frac{\frac{\sqrt{3937609}}{625}-\frac{181}{250}}{7.8496}
Now solve the equation x=\frac{-0.724±\frac{\sqrt{3937609}}{625}}{7.8496} when ± is plus. Add -0.724 to \frac{\sqrt{3937609}}{625}.
x=\frac{\sqrt{3937609}}{4906}-\frac{905}{9812}
Divide -\frac{181}{250}+\frac{\sqrt{3937609}}{625} by 7.8496 by multiplying -\frac{181}{250}+\frac{\sqrt{3937609}}{625} by the reciprocal of 7.8496.
x=\frac{-\frac{\sqrt{3937609}}{625}-\frac{181}{250}}{7.8496}
Now solve the equation x=\frac{-0.724±\frac{\sqrt{3937609}}{625}}{7.8496} when ± is minus. Subtract \frac{\sqrt{3937609}}{625} from -0.724.
x=-\frac{\sqrt{3937609}}{4906}-\frac{905}{9812}
Divide -\frac{181}{250}-\frac{\sqrt{3937609}}{625} by 7.8496 by multiplying -\frac{181}{250}-\frac{\sqrt{3937609}}{625} by the reciprocal of 7.8496.
x=\frac{\sqrt{3937609}}{4906}-\frac{905}{9812} x=-\frac{\sqrt{3937609}}{4906}-\frac{905}{9812}
The equation is now solved.
3.9248x^{2}+0.724x-0.6087=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
3.9248x^{2}+0.724x-0.6087-\left(-0.6087\right)=-\left(-0.6087\right)
Add 0.6087 to both sides of the equation.
3.9248x^{2}+0.724x=-\left(-0.6087\right)
Subtracting -0.6087 from itself leaves 0.
3.9248x^{2}+0.724x=0.6087
Subtract -0.6087 from 0.
\frac{3.9248x^{2}+0.724x}{3.9248}=\frac{0.6087}{3.9248}
Divide both sides of the equation by 3.9248, which is the same as multiplying both sides by the reciprocal of the fraction.
x^{2}+\frac{0.724}{3.9248}x=\frac{0.6087}{3.9248}
Dividing by 3.9248 undoes the multiplication by 3.9248.
x^{2}+\frac{905}{4906}x=\frac{0.6087}{3.9248}
Divide 0.724 by 3.9248 by multiplying 0.724 by the reciprocal of 3.9248.
x^{2}+\frac{905}{4906}x=\frac{6087}{39248}
Divide 0.6087 by 3.9248 by multiplying 0.6087 by the reciprocal of 3.9248.
x^{2}+\frac{905}{4906}x+\frac{905}{9812}^{2}=\frac{6087}{39248}+\frac{905}{9812}^{2}
Divide \frac{905}{4906}, the coefficient of the x term, by 2 to get \frac{905}{9812}. Then add the square of \frac{905}{9812} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+\frac{905}{4906}x+\frac{819025}{96275344}=\frac{6087}{39248}+\frac{819025}{96275344}
Square \frac{905}{9812} by squaring both the numerator and the denominator of the fraction.
x^{2}+\frac{905}{4906}x+\frac{819025}{96275344}=\frac{3937609}{24068836}
Add \frac{6087}{39248} to \frac{819025}{96275344} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(x+\frac{905}{9812}\right)^{2}=\frac{3937609}{24068836}
Factor x^{2}+\frac{905}{4906}x+\frac{819025}{96275344}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+\frac{905}{9812}\right)^{2}}=\sqrt{\frac{3937609}{24068836}}
Take the square root of both sides of the equation.
x+\frac{905}{9812}=\frac{\sqrt{3937609}}{4906} x+\frac{905}{9812}=-\frac{\sqrt{3937609}}{4906}
Simplify.
x=\frac{\sqrt{3937609}}{4906}-\frac{905}{9812} x=-\frac{\sqrt{3937609}}{4906}-\frac{905}{9812}
Subtract \frac{905}{9812} from both sides of the equation.