Solve 3.8+41/4-31/4-72/5

$$3.8 + 4 \frac { 1 } { 4 } - 3 \frac { 1 } { 4 } - 7 \frac { 2 } { 5 }$$

Evaluate

$$-2.6$$

Solution Steps

Multiply 4 and 4 to get 16.

$$3.8+\frac{16+1}{4}-\frac{3\times 4+1}{4}-\frac{7\times 5+2}{5}$$

Add 16 and 1 to get 17.

$$3.8+\frac{17}{4}-\frac{3\times 4+1}{4}-\frac{7\times 5+2}{5}$$

Convert decimal number 3.8 to fraction \frac{38}{10}. Reduce the fraction \frac{38}{10} to lowest terms by extracting and canceling out 2.

$$\frac{19}{5}+\frac{17}{4}-\frac{3\times 4+1}{4}-\frac{7\times 5+2}{5}$$

Least common multiple of 5 and 4 is 20. Convert \frac{19}{5} and \frac{17}{4} to fractions with denominator 20.

$$\frac{76}{20}+\frac{85}{20}-\frac{3\times 4+1}{4}-\frac{7\times 5+2}{5}$$

Since \frac{76}{20} and \frac{85}{20} have the same denominator, add them by adding their numerators.

$$\frac{76+85}{20}-\frac{3\times 4+1}{4}-\frac{7\times 5+2}{5}$$

Add 76 and 85 to get 161.

$$\frac{161}{20}-\frac{3\times 4+1}{4}-\frac{7\times 5+2}{5}$$

Multiply 3 and 4 to get 12.

$$\frac{161}{20}-\frac{12+1}{4}-\frac{7\times 5+2}{5}$$

Add 12 and 1 to get 13.

$$\frac{161}{20}-\frac{13}{4}-\frac{7\times 5+2}{5}$$

Least common multiple of 20 and 4 is 20. Convert \frac{161}{20} and \frac{13}{4} to fractions with denominator 20.

$$\frac{161}{20}-\frac{65}{20}-\frac{7\times 5+2}{5}$$

Since \frac{161}{20} and \frac{65}{20} have the same denominator, subtract them by subtracting their numerators.

$$\frac{161-65}{20}-\frac{7\times 5+2}{5}$$

Subtract 65 from 161 to get 96.

$$\frac{96}{20}-\frac{7\times 5+2}{5}$$

Reduce the fraction \frac{96}{20} to lowest terms by extracting and canceling out 4.

$$\frac{24}{5}-\frac{7\times 5+2}{5}$$

Multiply 7 and 5 to get 35.

$$\frac{24}{5}-\frac{35+2}{5}$$

Add 35 and 2 to get 37.

$$\frac{24}{5}-\frac{37}{5}$$

Since \frac{24}{5} and \frac{37}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{24-37}{5}$$

Subtract 37 from 24 to get -13.

$$-\frac{13}{5}$$

Factor

$$-2.6$$