Solve 3.5+7^0-2^3=p:2-1

$$3.5 + 7 ^ { 0 } - 2 ^ { 3 } = p : 2 - 1$$

Solve for p

$$p=-5$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$2\left(3.5+7^{0}\right)-2\times 2^{3}=p-2$$

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$2\left(3.5+7^{0}\right)-2^{4}=p-2$$

Calculate 7 to the power of 0 and get 1.

$$2\left(3.5+1\right)-2^{4}=p-2$$

Add 3.5 and 1 to get 4.5.

$$2\times 4.5-2^{4}=p-2$$

Multiply 2 and 4.5 to get 9.

$$9-2^{4}=p-2$$

Calculate 2 to the power of 4 and get 16.

$$9-16=p-2$$

Subtract 16 from 9 to get -7.

$$-7=p-2$$

Swap sides so that all variable terms are on the left hand side.

$$p-2=-7$$

Add 2 to both sides.

$$p=-7+2$$

Add -7 and 2 to get -5.

$$p=-5$$