Solve 3.4x-3y+12=0

$$3.4 x - 3 y + 12 = 0$$

Solve for x

$$x=\frac{15y-60}{17}$$

Steps for Solving Linear Equation

Add 3y to both sides. Anything plus zero gives itself.

$$3.4x+12=3y$$

Subtract 12 from both sides.

$$3.4x=3y-12$$

Divide both sides of the equation by 3.4, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{3.4x}{3.4}=\frac{3y-12}{3.4}$$

Dividing by 3.4 undoes the multiplication by 3.4.

$$x=\frac{3y-12}{3.4}$$

Divide -12+3y by 3.4 by multiplying -12+3y by the reciprocal of 3.4.

$$x=\frac{15y-60}{17}$$

Solve for y

$$y=\frac{17x}{15}+4$$

Steps for Solving Linear Equation

Subtract 3.4x from both sides. Anything subtracted from zero gives its negation.

$$-3y+12=-3.4x$$

Subtract 12 from both sides.

$$-3y=-3.4x-12$$

The equation is in standard form.

$$-3y=-\frac{17x}{5}-12$$

Divide both sides by -3.

$$\frac{-3y}{-3}=\frac{-\frac{17x}{5}-12}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$y=\frac{-\frac{17x}{5}-12}{-3}$$

Divide -\frac{17x}{5}-12 by -3.

$$y=\frac{17x}{15}+4$$