Solve 3-xdivx^2+15-8x

$$3-x \div { x }^{ 2 } +15-8x$$

Evaluate

$$-8x+18-\frac{1}{x}$$

Short Solution Steps

Rewrite x^{2} as xx. Cancel out x in both numerator and denominator.

$$3-\frac{1}{x}+15-8x$$

Add 3 and 15 to get 18.

$$18-\frac{1}{x}-8x$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 18-8x times \frac{x}{x}.

$$\frac{\left(18-8x\right)x}{x}-\frac{1}{x}$$

Since \frac{\left(18-8x\right)x}{x} and \frac{1}{x} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\left(18-8x\right)x-1}{x}$$

Do the multiplications in \left(18-8x\right)x-1.

$$\frac{18x-8x^{2}-1}{x}$$

Factor

$$-\frac{8\left(x-\frac{9-\sqrt{73}}{8}\right)\left(x-\frac{\sqrt{73}+9}{8}\right)}{x}$$