Solve 3-4sqrt{1-5x}=-7

$$3-4 \sqrt{ 1-5x } =-7$$

Solve for x

$$x = -\frac{21}{20} = -1\frac{1}{20} = -1.05$$

Steps for Solving Radical Equations

Subtract 3 from both sides of the equation.

$$-4\sqrt{-5x+1}+3-3=-7-3$$

Subtracting 3 from itself leaves 0.

$$-4\sqrt{-5x+1}=-7-3$$

Subtract 3 from -7.

$$-4\sqrt{-5x+1}=-10$$

Divide both sides by -4.

$$\frac{-4\sqrt{-5x+1}}{-4}=-\frac{10}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$\sqrt{-5x+1}=-\frac{10}{-4}$$

Reduce the fraction \frac{-10}{-4} to lowest terms by extracting and canceling out 2.

$$\sqrt{-5x+1}=\frac{5}{2}$$

Square both sides of the equation.

$$-5x+1=\frac{25}{4}$$

Subtract 1 from both sides of the equation.

$$-5x+1-1=\frac{25}{4}-1$$

Subtracting 1 from itself leaves 0.

$$-5x=\frac{25}{4}-1$$

Subtract 1 from \frac{25}{4}.

$$-5x=\frac{21}{4}$$

Divide both sides by -5.

$$\frac{-5x}{-5}=\frac{\frac{21}{4}}{-5}$$

Dividing by -5 undoes the multiplication by -5.

$$x=\frac{\frac{21}{4}}{-5}$$

Divide \frac{21}{4} by -5.

$$x=-\frac{21}{20}$$