Solve 3-(5-(2-(2+5div7*3

$$3-(5-(2-(2+5 \div 7 \times 3$$

Evaluate

$$-\frac{29}{7}\approx -4.142857143$$

Solution Steps

Express \frac{5}{7}\times 3 as a single fraction.

$$3-\left(5-\left(2-\left(2+\frac{5\times 3}{7}\right)\right)\right)$$

Multiply 5 and 3 to get 15.

$$3-\left(5-\left(2-\left(2+\frac{15}{7}\right)\right)\right)$$

Convert 2 to fraction \frac{14}{7}.

$$3-\left(5-\left(2-\left(\frac{14}{7}+\frac{15}{7}\right)\right)\right)$$

Since \frac{14}{7} and \frac{15}{7} have the same denominator, add them by adding their numerators.

$$3-\left(5-\left(2-\frac{14+15}{7}\right)\right)$$

Add 14 and 15 to get 29.

$$3-\left(5-\left(2-\frac{29}{7}\right)\right)$$

Convert 2 to fraction \frac{14}{7}.

$$3-\left(5-\left(\frac{14}{7}-\frac{29}{7}\right)\right)$$

Since \frac{14}{7} and \frac{29}{7} have the same denominator, subtract them by subtracting their numerators.

$$3-\left(5-\frac{14-29}{7}\right)$$

Subtract 29 from 14 to get -15.

$$3-\left(5-\left(-\frac{15}{7}\right)\right)$$

The opposite of -\frac{15}{7} is \frac{15}{7}.

$$3-\left(5+\frac{15}{7}\right)$$

Convert 5 to fraction \frac{35}{7}.

$$3-\left(\frac{35}{7}+\frac{15}{7}\right)$$

Since \frac{35}{7} and \frac{15}{7} have the same denominator, add them by adding their numerators.

$$3-\frac{35+15}{7}$$

Add 35 and 15 to get 50.

$$3-\frac{50}{7}$$

Convert 3 to fraction \frac{21}{7}.

$$\frac{21}{7}-\frac{50}{7}$$

Since \frac{21}{7} and \frac{50}{7} have the same denominator, subtract them by subtracting their numerators.

$$\frac{21-50}{7}$$

Subtract 50 from 21 to get -29.

$$-\frac{29}{7}$$

Factor

$$-\frac{29}{7} = -4\frac{1}{7} = -4.142857142857143$$