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3-\frac{\left(1\times 12+11\right)\times 21}{12\left(2\times 21+4\right)}
Divide \frac{1\times 12+11}{12} by \frac{2\times 21+4}{21} by multiplying \frac{1\times 12+11}{12} by the reciprocal of \frac{2\times 21+4}{21}.
3-\frac{7\left(11+12\right)}{4\left(4+2\times 21\right)}
Cancel out 3 in both numerator and denominator.
3-\frac{7\times 23}{4\left(4+2\times 21\right)}
Add 11 and 12 to get 23.
3-\frac{161}{4\left(4+2\times 21\right)}
Multiply 7 and 23 to get 161.
3-\frac{161}{4\left(4+42\right)}
Multiply 2 and 21 to get 42.
3-\frac{161}{4\times 46}
Add 4 and 42 to get 46.
3-\frac{161}{184}
Multiply 4 and 46 to get 184.
3-\frac{7}{8}
Reduce the fraction \frac{161}{184} to lowest terms by extracting and canceling out 23.
\frac{24}{8}-\frac{7}{8}
Convert 3 to fraction \frac{24}{8}.
\frac{24-7}{8}
Since \frac{24}{8} and \frac{7}{8} have the same denominator, subtract them by subtracting their numerators.
\frac{17}{8}
Subtract 7 from 24 to get 17.