Solve 3-2^3-2(-2^2)-4*2+1

$$3- { 2 }^{ 3 } -2( { -2 }^{ 2 } )-4 \cdot 2+1$$

Evaluate

$$-20$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$3-8-2\left(-2\right)^{2}-4\times 2+1$$

Subtract 8 from 3 to get -5.

$$-5-2\left(-2\right)^{2}-4\times 2+1$$

Calculate -2 to the power of 2 and get 4.

$$-5-2\times 4-4\times 2+1$$

Multiply 2 and 4 to get 8.

$$-5-8-4\times 2+1$$

Subtract 8 from -5 to get -13.

$$-13-4\times 2+1$$

Multiply 4 and 2 to get 8.

$$-13-8+1$$

Subtract 8 from -13 to get -21.

$$-21+1$$

Add -21 and 1 to get -20.

$$-20$$

Factor

$$-20$$