Solve 3-sqrt{x}=5y/4

$$3- \sqrt{ x } = \frac{ 5y }{ 4 }$$

Solve for y (complex solution)

$$y=\frac{-4\sqrt{x}+12}{5}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 4.

$$12-4\sqrt{x}=5y$$

Swap sides so that all variable terms are on the left hand side.

$$5y=12-4\sqrt{x}$$

The equation is in standard form.

$$5y=-4\sqrt{x}+12$$

Divide both sides by 5.

$$\frac{5y}{5}=\frac{-4\sqrt{x}+12}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$y=\frac{-4\sqrt{x}+12}{5}$$

Solve for x

$$x=\frac{\left(12-5y\right)^{2}}{16}$$

$$-\frac{5y}{4}+3\geq 0$$

Steps for Solving Radical Equations

Subtract 3 from both sides of the equation.

$$-\sqrt{x}+3-3=\frac{5y}{4}-3$$

Subtracting 3 from itself leaves 0.

$$-\sqrt{x}=\frac{5y}{4}-3$$

Divide both sides by -1.

$$\frac{-\sqrt{x}}{-1}=\frac{\frac{5y}{4}-3}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$\sqrt{x}=\frac{\frac{5y}{4}-3}{-1}$$

Divide \frac{5y}{4}-3 by -1.

$$\sqrt{x}=-\frac{5y}{4}+3$$

Square both sides of the equation.

$$x=\frac{\left(12-5y\right)^{2}}{16}$$

Solve for y

$$y=\frac{-4\sqrt{x}+12}{5}$$

$$x\geq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 4.

$$12-4\sqrt{x}=5y$$

Swap sides so that all variable terms are on the left hand side.

$$5y=12-4\sqrt{x}$$

The equation is in standard form.

$$5y=-4\sqrt{x}+12$$

Divide both sides by 5.

$$\frac{5y}{5}=\frac{-4\sqrt{x}+12}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$y=\frac{-4\sqrt{x}+12}{5}$$

Solve for x (complex solution)

$$x=\frac{\left(12-5y\right)^{2}}{16}$$

$$y=\frac{12}{5}\text{ or }arg(-\frac{5y}{4}+3)<\pi$$