Solve 3-sqrt{49}+2(3+4^2div1/2

$$3- \sqrt{ 49 } +2(3+ { 4 }^{ 2 } \div \frac{ 1 }{ 2 }$$

Evaluate

$$66$$

Solution Steps

Calculate the square root of 49 and get 7.

$$3-7+2\left(3+\frac{4^{2}}{\frac{1}{2}}\right)$$

Subtract 7 from 3 to get -4.

$$-4+2\left(3+\frac{4^{2}}{\frac{1}{2}}\right)$$

Calculate 4 to the power of 2 and get 16.

$$-4+2\left(3+\frac{16}{\frac{1}{2}}\right)$$

Divide 16 by \frac{1}{2} by multiplying 16 by the reciprocal of \frac{1}{2}.

$$-4+2\left(3+16\times 2\right)$$

Multiply 16 and 2 to get 32.

$$-4+2\left(3+32\right)$$

Add 3 and 32 to get 35.

$$-4+2\times 35$$

Multiply 2 and 35 to get 70.

$$-4+70$$

Add -4 and 70 to get 66.

$$66$$

Factor

$$2\times 3\times 11$$