Solve 3-lfloor6left(4-6right)+2left(5-6right)rfloor

$$3- \lfloor 6 \left( 4-6 \right) +2 \left( 5-6 \right) \rfloor$$

Evaluate

$$17$$

Solution Steps

Subtract 6 from 4 to get -2.

$$3-\lfloor 6\left(-2\right)+2\left(5-6\right)\rfloor$$

Multiply 6 and -2 to get -12.

$$3-\lfloor -12+2\left(5-6\right)\rfloor$$

Subtract 6 from 5 to get -1.

$$3-\lfloor -12+2\left(-1\right)\rfloor$$

Multiply 2 and -1 to get -2.

$$3-\lfloor -12-2\rfloor$$

Subtract 2 from -12 to get -14.

$$3-\lfloor -14\rfloor$$

The floor of a real number a is the largest integer number less than or equal to a. The floor of -14 is -14.

$$3-\left(-14\right)$$

The opposite of -14 is 14.

$$3+14$$

Add 3 and 14 to get 17.

$$17$$

Factor

$$17$$