Solve 3(y-6)+4(-4-y)=-12(y-3)+4

$$3(y-6)+4(-4-y)=-12(y-3)+4$$

Solve for y

$$y = \frac{74}{11} = 6\frac{8}{11} \approx 6.727272727$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3 by y-6.

$$3y-18+4\left(-4-y\right)=-12\left(y-3\right)+4$$

Use the distributive property to multiply 4 by -4-y.

$$3y-18-16-4y=-12\left(y-3\right)+4$$

Subtract 16 from -18 to get -34.

$$3y-34-4y=-12\left(y-3\right)+4$$

Combine 3y and -4y to get -y.

$$-y-34=-12\left(y-3\right)+4$$

Use the distributive property to multiply -12 by y-3.

$$-y-34=-12y+36+4$$

Add 36 and 4 to get 40.

$$-y-34=-12y+40$$

Add 12y to both sides.

$$-y-34+12y=40$$

Combine -y and 12y to get 11y.

$$11y-34=40$$

Add 34 to both sides.

$$11y=40+34$$

Add 40 and 34 to get 74.

$$11y=74$$

Divide both sides by 11.

$$y=\frac{74}{11}$$