Solve 3(x-3)-4(y+2)=0

$$3(x-3)-4(y+2)=0$$

Solve for x

$$x=\frac{4y+17}{3}$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3 by x-3.

$$3x-9-4\left(y+2\right)=0$$

Use the distributive property to multiply -4 by y+2.

$$3x-9-4y-8=0$$

Subtract 8 from -9 to get -17.

$$3x-17-4y=0$$

Add 17 to both sides. Anything plus zero gives itself.

$$3x-4y=17$$

Add 4y to both sides.

$$3x=17+4y$$

The equation is in standard form.

$$3x=4y+17$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{4y+17}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{4y+17}{3}$$

Solve for y

$$y=\frac{3x-17}{4}$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3 by x-3.

$$3x-9-4\left(y+2\right)=0$$

Use the distributive property to multiply -4 by y+2.

$$3x-9-4y-8=0$$

Subtract 8 from -9 to get -17.

$$3x-17-4y=0$$

Subtract 3x from both sides. Anything subtracted from zero gives its negation.

$$-17-4y=-3x$$

Add 17 to both sides.

$$-4y=-3x+17$$

The equation is in standard form.

$$-4y=17-3x$$

Divide both sides by -4.

$$\frac{-4y}{-4}=\frac{17-3x}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$y=\frac{17-3x}{-4}$$

Divide -3x+17 by -4.

$$y=\frac{3x-17}{4}$$