Solve 3(x+1)<4(x+2)-3

$$3(x+1) < 4(x+2)-3$$

Solve for x

$$x>-2$$

Solution Steps

Use the distributive property to multiply 3 by x+1.

$$3x+3<4\left(x+2\right)-3$$

Use the distributive property to multiply 4 by x+2.

$$3x+3<4x+8-3$$

Subtract 3 from 8 to get 5.

$$3x+3<4x+5$$

Subtract 4x from both sides.

$$3x+3-4x<5$$

Combine 3x and -4x to get -x.

$$-x+3<5$$

Subtract 3 from both sides.

$$-x<5-3$$

Subtract 3 from 5 to get 2.

$$-x<2$$

Divide both sides by -1. Since -1 is negative, the inequality direction is changed.

$$x>-2$$