Solve 3(b(12)-1)+x=5(12)+3

$$3(b(12)-1)+x = 5(12)+3$$

Solve for b

$$b=-\frac{x}{36}+\frac{11}{6}$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3 by b\times 12-1.

$$3b\times 12-3+x=5\times 12+3$$

Multiply 3 and 12 to get 36.

$$36b-3+x=5\times 12+3$$

Multiply 5 and 12 to get 60.

$$36b-3+x=60+3$$

Add 60 and 3 to get 63.

$$36b-3+x=63$$

Add 3 to both sides.

$$36b+x=63+3$$

Add 63 and 3 to get 66.

$$36b+x=66$$

Subtract x from both sides.

$$36b=66-x$$

Divide both sides by 36.

$$\frac{36b}{36}=\frac{66-x}{36}$$

Dividing by 36 undoes the multiplication by 36.

$$b=\frac{66-x}{36}$$

Divide 66-x by 36.

$$b=-\frac{x}{36}+\frac{11}{6}$$

Solve for x

$$x=66-36b$$

Solution Steps

Use the distributive property to multiply 3 by b\times 12-1.

$$3b\times 12-3+x=5\times 12+3$$

Multiply 3 and 12 to get 36.

$$36b-3+x=5\times 12+3$$

Multiply 5 and 12 to get 60.

$$36b-3+x=60+3$$

Add 60 and 3 to get 63.

$$36b-3+x=63$$

Subtract 36b from both sides.

$$-3+x=63-36b$$

Add 3 to both sides.

$$x=63-36b+3$$

Add 63 and 3 to get 66.

$$x=66-36b$$