Solve 3(-25x+100)=5(14x-25)-200

$$3(-25x+100)=5(14x-25)-200$$

Solve for x

$$x = \frac{125}{29} = 4\frac{9}{29} \approx 4.310344828$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3 by -25x+100.

$$-75x+300=5\left(14x-25\right)-200$$

Use the distributive property to multiply 5 by 14x-25.

$$-75x+300=70x-125-200$$

Subtract 200 from -125 to get -325.

$$-75x+300=70x-325$$

Subtract 70x from both sides.

$$-75x+300-70x=-325$$

Combine -75x and -70x to get -145x.

$$-145x+300=-325$$

Subtract 300 from both sides.

$$-145x=-325-300$$

Subtract 300 from -325 to get -625.

$$-145x=-625$$

Divide both sides by -145.

$$x=\frac{-625}{-145}$$

Reduce the fraction \frac{-625}{-145} to lowest terms by extracting and canceling out -5.

$$x=\frac{125}{29}$$