Solve 3(3^2-(2*3*-4)+(4*3*-4)-5

$$3( { 3 }^{ 2 } -(2 \times 3 \times -4)+(4 \times 3 \times -4)-5$$

Evaluate

$$-60$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$3\left(9-2\times 3\left(-4\right)+4\times 3\left(-4\right)-5\right)$$

Multiply 2 and 3 to get 6.

$$3\left(9-6\left(-4\right)+4\times 3\left(-4\right)-5\right)$$

Multiply 6 and -4 to get -24.

$$3\left(9-\left(-24\right)+4\times 3\left(-4\right)-5\right)$$

The opposite of -24 is 24.

$$3\left(9+24+4\times 3\left(-4\right)-5\right)$$

Add 9 and 24 to get 33.

$$3\left(33+4\times 3\left(-4\right)-5\right)$$

Multiply 4 and 3 to get 12.

$$3\left(33+12\left(-4\right)-5\right)$$

Multiply 12 and -4 to get -48.

$$3\left(33-48-5\right)$$

Subtract 48 from 33 to get -15.

$$3\left(-15-5\right)$$

Subtract 5 from -15 to get -20.

$$3\left(-20\right)$$

Multiply 3 and -20 to get -60.

$$-60$$

Factor

$$-60$$