Solve 3(41*13/28)+3(18*13/27)

$$3( \frac{ 41 \times 13 }{ 28 } )+3( \frac{ 18 \times 13 }{ 27 } )$$

Evaluate

$$\frac{2327}{28}\approx 83.107142857$$

Solution Steps

Multiply 41 and 13 to get 533.

$$3\times \frac{533}{28}+3\times \frac{18\times 13}{27}$$

Express 3\times \frac{533}{28} as a single fraction.

$$\frac{3\times 533}{28}+3\times \frac{18\times 13}{27}$$

Multiply 3 and 533 to get 1599.

$$\frac{1599}{28}+3\times \frac{18\times 13}{27}$$

Multiply 18 and 13 to get 234.

$$\frac{1599}{28}+3\times \frac{234}{27}$$

Reduce the fraction \frac{234}{27} to lowest terms by extracting and canceling out 9.

$$\frac{1599}{28}+3\times \frac{26}{3}$$

Cancel out 3 and 3.

$$\frac{1599}{28}+26$$

Convert 26 to fraction \frac{728}{28}.

$$\frac{1599}{28}+\frac{728}{28}$$

Since \frac{1599}{28} and \frac{728}{28} have the same denominator, add them by adding their numerators.

$$\frac{1599+728}{28}$$

Add 1599 and 728 to get 2327.

$$\frac{2327}{28}$$

Factor

$$\frac{13 \cdot 179}{2 ^ {2} \cdot 7} = 83\frac{3}{28} = 83.10714285714286$$