Solve 3=17-x/1-(-3)

$$3= \frac{ 17-x }{ 1-(-3) }$$

Solve for x

$$x=5$$

Steps for Solving Linear Equation

The opposite of -3 is 3.

$$3=\frac{17-x}{1+3}$$

Add 1 and 3 to get 4.

$$3=\frac{17-x}{4}$$

Divide each term of 17-x by 4 to get \frac{17}{4}-\frac{1}{4}x.

$$3=\frac{17}{4}-\frac{1}{4}x$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{17}{4}-\frac{1}{4}x=3$$

Subtract \frac{17}{4} from both sides.

$$-\frac{1}{4}x=3-\frac{17}{4}$$

Convert 3 to fraction \frac{12}{4}.

$$-\frac{1}{4}x=\frac{12}{4}-\frac{17}{4}$$

Since \frac{12}{4} and \frac{17}{4} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{1}{4}x=\frac{12-17}{4}$$

Subtract 17 from 12 to get -5.

$$-\frac{1}{4}x=-\frac{5}{4}$$

Multiply both sides by -4, the reciprocal of -\frac{1}{4}.

$$x=-\frac{5}{4}\left(-4\right)$$

Express -\frac{5}{4}\left(-4\right) as a single fraction.

$$x=\frac{-5\left(-4\right)}{4}$$

Multiply -5 and -4 to get 20.

$$x=\frac{20}{4}$$

Divide 20 by 4 to get 5.

$$x=5$$