Solve 3z-2+4(1-z)=5(1-2z)-12

$$3 z - 2 + 4 ( 1 - z ) = 5 ( 1 - 2 z ) - 12$$

Solve for z

$$z=-1$$

Steps for Solving Linear Equation

Use the distributive property to multiply 4 by 1-z.

$$3z-2+4-4z=5\left(1-2z\right)-12$$

Add -2 and 4 to get 2.

$$3z+2-4z=5\left(1-2z\right)-12$$

Combine 3z and -4z to get -z.

$$-z+2=5\left(1-2z\right)-12$$

Use the distributive property to multiply 5 by 1-2z.

$$-z+2=5-10z-12$$

Subtract 12 from 5 to get -7.

$$-z+2=-7-10z$$

Add 10z to both sides.

$$-z+2+10z=-7$$

Combine -z and 10z to get 9z.

$$9z+2=-7$$

Subtract 2 from both sides.

$$9z=-7-2$$

Subtract 2 from -7 to get -9.

$$9z=-9$$

Divide both sides by 9.

$$z=\frac{-9}{9}$$

Divide -9 by 9 to get -1.

$$z=-1$$