Solve 3z+12,6z+24

$$3 z + 12,6 z + 24$$

Differentiate w.r.t. z

$$15,6$$

Steps Using Derivative Rule for Sum

Combine 3z and 12,6z to get 15,6z.

$$\frac{\mathrm{d}}{\mathrm{d}z}(15,6z+24)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$15,6z^{1-1}$$

Subtract 1 from 1.

$$15,6z^{0}$$

For any term t except 0, t^{0}=1.

$$15,6\times 1$$

For any term t, t\times 1=t and 1t=t.

$$15,6$$

Evaluate

$$\frac{78z}{5}+24$$

Solution Steps

Combine 3z and 12,6z to get 15,6z.

$$15,6z+24$$