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2y+\frac{2}{5}y+\frac{12}{5}y=2y
Combine 3y and -y to get 2y.
\frac{12}{5}y+\frac{12}{5}y=2y
Combine 2y and \frac{2}{5}y to get \frac{12}{5}y.
\frac{24}{5}y=2y
Combine \frac{12}{5}y and \frac{12}{5}y to get \frac{24}{5}y.
\frac{24}{5}y-2y=0
Subtract 2y from both sides.
\frac{14}{5}y=0
Combine \frac{24}{5}y and -2y to get \frac{14}{5}y.
y=0
Product of two numbers is equal to 0 if at least one of them is 0. Since \frac{14}{5} is not equal to 0, y must be equal to 0.