Solve for x
x=\frac{y}{3}-\frac{8}{9}
Solve for y
y=3x+\frac{8}{3}
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-9x=8-3y
Subtract 3y from both sides.
\frac{-9x}{-9}=\frac{8-3y}{-9}
Divide both sides by -9.
x=\frac{8-3y}{-9}
Dividing by -9 undoes the multiplication by -9.
x=\frac{y}{3}-\frac{8}{9}
Divide 8-3y by -9.
3y=8+9x
Add 9x to both sides.
3y=9x+8
The equation is in standard form.
\frac{3y}{3}=\frac{9x+8}{3}
Divide both sides by 3.
y=\frac{9x+8}{3}
Dividing by 3 undoes the multiplication by 3.
y=3x+\frac{8}{3}
Divide 8+9x by 3.
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