Solve for x
x=\frac{3y}{8}+\frac{23}{4}
Solve for y
y=\frac{8x-46}{3}
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-8x=-46-3y
Subtract 3y from both sides.
-8x=-3y-46
The equation is in standard form.
\frac{-8x}{-8}=\frac{-3y-46}{-8}
Divide both sides by -8.
x=\frac{-3y-46}{-8}
Dividing by -8 undoes the multiplication by -8.
x=\frac{3y}{8}+\frac{23}{4}
Divide -46-3y by -8.
3y=-46+8x
Add 8x to both sides.
3y=8x-46
The equation is in standard form.
\frac{3y}{3}=\frac{8x-46}{3}
Divide both sides by 3.
y=\frac{8x-46}{3}
Dividing by 3 undoes the multiplication by 3.
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