Solve 3y-3x+4=0

$$3 y - 3 x + 4 = 0$$

Solve for x

$$x = \frac{4}{3} = 1\frac{1}{3} = 1.3333333333333333$$

Steps for Solving Linear Equation

Subtract 3y from both sides. Anything subtracted from zero gives its negation.

$$-3x+4=-3y$$

Subtract 4 from both sides.

$$-3x=-3y-4$$

Divide both sides by -3.

$$\frac{-3x}{-3}=\frac{-3y-4}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$x=\frac{-3y-4}{-3}$$

Divide -3y-4 by -3.

$$x=y+\frac{4}{3}$$

Solve for y

$$y = -\frac{4}{3} = -1\frac{1}{3} = -1.3333333333333333$$

Steps for Solving Linear Equation

Add 3x to both sides. Anything plus zero gives itself.

$$3y+4=3x$$

Subtract 4 from both sides.

$$3y=3x-4$$

Divide both sides by 3.

$$\frac{3y}{3}=\frac{3x-4}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$y=\frac{3x-4}{3}$$

Divide 3x-4 by 3.

$$y=x-\frac{4}{3}$$