Solve 3y-1=2yz

$$3 y - 1 = 2 y z$$

Solve for y

$$y=\frac{1}{3-2z}$$

$$z\neq \frac{3}{2}$$

Steps for Solving Linear Equation

Subtract 2yz from both sides.

$$3y-1-2yz=0$$

Add 1 to both sides. Anything plus zero gives itself.

$$3y-2yz=1$$

Combine all terms containing y.

$$\left(3-2z\right)y=1$$

Divide both sides by 3-2z.

$$\frac{\left(3-2z\right)y}{3-2z}=\frac{1}{3-2z}$$

Dividing by 3-2z undoes the multiplication by 3-2z.

$$y=\frac{1}{3-2z}$$

Solve for z

$$z=\frac{3}{2}-\frac{1}{2y}$$

$$y\neq 0$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$2yz=3y-1$$

Divide both sides by 2y.

$$\frac{2yz}{2y}=\frac{3y-1}{2y}$$

Dividing by 2y undoes the multiplication by 2y.

$$z=\frac{3y-1}{2y}$$

Divide 3y-1 by 2y.

$$z=\frac{3}{2}-\frac{1}{2y}$$