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3y-\frac{4}{3}+\frac{1}{5}y=\frac{6}{5}
Add \frac{1}{5}y to both sides.
\frac{16}{5}y-\frac{4}{3}=\frac{6}{5}
Combine 3y and \frac{1}{5}y to get \frac{16}{5}y.
\frac{16}{5}y=\frac{6}{5}+\frac{4}{3}
Add \frac{4}{3} to both sides.
\frac{16}{5}y=\frac{18}{15}+\frac{20}{15}
Least common multiple of 5 and 3 is 15. Convert \frac{6}{5} and \frac{4}{3} to fractions with denominator 15.
\frac{16}{5}y=\frac{18+20}{15}
Since \frac{18}{15} and \frac{20}{15} have the same denominator, add them by adding their numerators.
\frac{16}{5}y=\frac{38}{15}
Add 18 and 20 to get 38.
y=\frac{38}{15}\times \frac{5}{16}
Multiply both sides by \frac{5}{16}, the reciprocal of \frac{16}{5}.
y=\frac{38\times 5}{15\times 16}
Multiply \frac{38}{15} times \frac{5}{16} by multiplying numerator times numerator and denominator times denominator.
y=\frac{190}{240}
Do the multiplications in the fraction \frac{38\times 5}{15\times 16}.
y=\frac{19}{24}
Reduce the fraction \frac{190}{240} to lowest terms by extracting and canceling out 10.