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3\left(-1\right)-\frac{1}{2}x-x=4
Consider the first equation. Insert the known values of variables into the equation.
-3-\frac{1}{2}x-x=4
Multiply 3 and -1 to get -3.
-3-\frac{3}{2}x=4
Combine -\frac{1}{2}x and -x to get -\frac{3}{2}x.
-\frac{3}{2}x=4+3
Add 3 to both sides.
-\frac{3}{2}x=7
Add 4 and 3 to get 7.
x=7\left(-\frac{2}{3}\right)
Multiply both sides by -\frac{2}{3}, the reciprocal of -\frac{3}{2}.
x=-\frac{14}{3}
Multiply 7 and -\frac{2}{3} to get -\frac{14}{3}.
y=-1 x=-\frac{14}{3}
The system is now solved.