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3\left(y^{3}-8z^{3}\right)
Factor out 3.
\left(y-2z\right)\left(y^{2}+2yz+4z^{2}\right)
Consider y^{3}-8z^{3}. Rewrite y^{3}-8z^{3} as y^{3}-\left(2z\right)^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).
3\left(y-2z\right)\left(y^{2}+2yz+4z^{2}\right)
Rewrite the complete factored expression.