Solve 3y^2+30y-x+70=0

$$3 y ^ { 2 } + 30 y - x + 70 = 0$$

Solve for x

$$x=3y^{2}+30y+70$$

Steps for Solving Linear Equation

Subtract 3y^{2} from both sides. Anything subtracted from zero gives its negation.

$$30y-x+70=-3y^{2}$$

Subtract 30y from both sides.

$$-x+70=-3y^{2}-30y$$

Subtract 70 from both sides.

$$-x=-3y^{2}-30y-70$$

Divide both sides by -1.

$$\frac{-x}{-1}=\frac{-3y^{2}-30y-70}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x=\frac{-3y^{2}-30y-70}{-1}$$

Divide -3y^{2}-30y-70 by -1.

$$x=3y^{2}+30y+70$$

Solve for y (complex solution)

$$y=\frac{\sqrt{3x+15}}{3}-5$$

$$y=-\frac{\sqrt{3x+15}}{3}-5$$

Solve for y

$$y=\frac{\sqrt{3x+15}}{3}-5$$

$$y=-\frac{\sqrt{3x+15}}{3}-5\text{, }x\geq -5$$