Solve for x
x=-\frac{3y}{4}+\frac{9}{2}
Solve for y
y=-\frac{4x}{3}+6
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18-4x=3y
Swap sides so that all variable terms are on the left hand side.
-4x=3y-18
Subtract 18 from both sides.
\frac{-4x}{-4}=\frac{3y-18}{-4}
Divide both sides by -4.
x=\frac{3y-18}{-4}
Dividing by -4 undoes the multiplication by -4.
x=-\frac{3y}{4}+\frac{9}{2}
Divide -18+3y by -4.
3y=18-4x
The equation is in standard form.
\frac{3y}{3}=\frac{18-4x}{3}
Divide both sides by 3.
y=\frac{18-4x}{3}
Dividing by 3 undoes the multiplication by 3.
y=-\frac{4x}{3}+6
Divide 18-4x by 3.
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