Solve for x
x=6y+14
Solve for y
y=\frac{x-14}{6}
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\frac{1}{2}x=3y+7
Swap sides so that all variable terms are on the left hand side.
\frac{\frac{1}{2}x}{\frac{1}{2}}=\frac{3y+7}{\frac{1}{2}}
Multiply both sides by 2.
x=\frac{3y+7}{\frac{1}{2}}
Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.
x=6y+14
Divide 3y+7 by \frac{1}{2} by multiplying 3y+7 by the reciprocal of \frac{1}{2}.
3y=\frac{1}{2}x-7
Subtract 7 from both sides.
3y=\frac{x}{2}-7
The equation is in standard form.
\frac{3y}{3}=\frac{\frac{x}{2}-7}{3}
Divide both sides by 3.
y=\frac{\frac{x}{2}-7}{3}
Dividing by 3 undoes the multiplication by 3.
y=\frac{x}{6}-\frac{7}{3}
Divide \frac{x}{2}-7 by 3.
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