Solve 3y+4x^2=sqrt{15}

$$3 y + 4 x ^ { 2 } = \sqrt { 15 }$$

Solve for y

$$y=\frac{-4x^{2}+\sqrt{15}}{3}$$

Steps for Solving Linear Equation

Subtract 4x^{2} from both sides.

$$3y=\sqrt{15}-4x^{2}$$

The equation is in standard form.

$$3y=-4x^{2}+\sqrt{15}$$

Divide both sides by 3.

$$\frac{3y}{3}=\frac{-4x^{2}+\sqrt{15}}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$y=\frac{-4x^{2}+\sqrt{15}}{3}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{-3y+\sqrt{15}}}{2}$$

$$x=\frac{\sqrt{-3y+\sqrt{15}}}{2}$$

Solve for x

$$x=\frac{\sqrt{-3y+\sqrt{15}}}{2}$$

$$x=-\frac{\sqrt{-3y+\sqrt{15}}}{2}\text{, }y\leq \frac{\sqrt{15}}{3}$$