Solve 3y+12+x=0

$$3 y + 12 + x = 0$$

Solve for x

$$x=-3y-12$$

Solution Steps

Subtract 3y from both sides. Anything subtracted from zero gives its negation.

$$12+x=-3y$$

Subtract 12 from both sides.

$$x=-3y-12$$

Solve for y

$$y=-\frac{x}{3}-4$$

Steps for Solving Linear Equation

Subtract 12 from both sides. Anything subtracted from zero gives its negation.

$$3y+x=-12$$

Subtract x from both sides.

$$3y=-12-x$$

The equation is in standard form.

$$3y=-x-12$$

Divide both sides by 3.

$$\frac{3y}{3}=\frac{-x-12}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$y=\frac{-x-12}{3}$$

Divide -12-x by 3.

$$y=-\frac{x}{3}-4$$