Solve 3xz-7x-1=0

$$3 x z - 7 x - 1 = 0$$

Solve for x

$$x=\frac{1}{3z-7}$$

$$z\neq \frac{7}{3}$$

Steps for Solving Linear Equation

Add 1 to both sides. Anything plus zero gives itself.

$$3xz-7x=1$$

Combine all terms containing x.

$$\left(3z-7\right)x=1$$

Divide both sides by 3z-7.

$$\frac{\left(3z-7\right)x}{3z-7}=\frac{1}{3z-7}$$

Dividing by 3z-7 undoes the multiplication by 3z-7.

$$x=\frac{1}{3z-7}$$

Solve for z

$$z=\frac{7}{3}+\frac{1}{3x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Add 7x to both sides. Anything plus zero gives itself.

$$3xz-1=7x$$

Add 1 to both sides.

$$3xz=7x+1$$

Divide both sides by 3x.

$$\frac{3xz}{3x}=\frac{7x+1}{3x}$$

Dividing by 3x undoes the multiplication by 3x.

$$z=\frac{7x+1}{3x}$$

Divide 7x+1 by 3x.

$$z=\frac{7}{3}+\frac{1}{3x}$$