Solve 3xz+2xy=3xz-48x

$$3 x z + 2 x y = 3 x z - 48 x$$

Solve for x

$$\left\{\begin{matrix}\\x=0\text{, }&\text{unconditionally}\\x\in \mathrm{R}\text{, }&y=-24\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 3xz from both sides.

$$3xz+2xy-3xz=-48x$$

Combine 3xz and -3xz to get 0.

$$2xy=-48x$$

Add 48x to both sides.

$$2xy+48x=0$$

Combine all terms containing x.

$$\left(2y+48\right)x=0$$

Divide 0 by 2y+48.

$$x=0$$

Solve for y

$$\left\{\begin{matrix}\\y=-24\text{, }&\text{unconditionally}\\y\in \mathrm{R}\text{, }&x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 3xz from both sides.

$$2xy=3xz-48x-3xz$$

Combine 3xz and -3xz to get 0.

$$2xy=-48x$$

Divide both sides by 2x.

$$\frac{2xy}{2x}=-\frac{48x}{2x}$$

Dividing by 2x undoes the multiplication by 2x.

$$y=-\frac{48x}{2x}$$

Divide -48x by 2x.

$$y=-24$$