Solve 3xy=4y-3y+4

$$3 x y = 4 y - 3 y + 4$$

Solve for x

$$x=\frac{1}{3}+\frac{4}{3y}$$

$$y\neq 0$$

Steps for Solving Linear Equation

Combine 4y and -3y to get y.

$$3xy=y+4$$

The equation is in standard form.

$$3yx=y+4$$

Divide both sides by 3y.

$$\frac{3yx}{3y}=\frac{y+4}{3y}$$

Dividing by 3y undoes the multiplication by 3y.

$$x=\frac{y+4}{3y}$$

Divide y+4 by 3y.

$$x=\frac{1}{3}+\frac{4}{3y}$$

Solve for y

$$y=\frac{4}{3x-1}$$

$$x\neq \frac{1}{3}$$

Steps for Solving Linear Equation

Combine 4y and -3y to get y.

$$3xy=y+4$$

Subtract y from both sides.

$$3xy-y=4$$

Combine all terms containing y.

$$\left(3x-1\right)y=4$$

Divide both sides by 3x-1.

$$\frac{\left(3x-1\right)y}{3x-1}=\frac{4}{3x-1}$$

Dividing by 3x-1 undoes the multiplication by 3x-1.

$$y=\frac{4}{3x-1}$$