Solve for x
x=\frac{y+10}{3}
Solve for y
y=3x-10
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3x-10=y
Add y to both sides. Anything plus zero gives itself.
3x=y+10
Add 10 to both sides.
\frac{3x}{3}=\frac{y+10}{3}
Divide both sides by 3.
x=\frac{y+10}{3}
Dividing by 3 undoes the multiplication by 3.
-y-10=-3x
Subtract 3x from both sides. Anything subtracted from zero gives its negation.
-y=-3x+10
Add 10 to both sides.
-y=10-3x
The equation is in standard form.
\frac{-y}{-1}=\frac{10-3x}{-1}
Divide both sides by -1.
y=\frac{10-3x}{-1}
Dividing by -1 undoes the multiplication by -1.
y=3x-10
Divide -3x+10 by -1.
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Limits
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