Solve for x
x=-\frac{3y-8}{3-y}
y\neq 3
Solve for y
y=-\frac{3x-8}{3-x}
x\neq 3
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3x-xy=8-3y
Subtract 3y from both sides.
\left(3-y\right)x=8-3y
Combine all terms containing x.
\frac{\left(3-y\right)x}{3-y}=\frac{8-3y}{3-y}
Divide both sides by 3-y.
x=\frac{8-3y}{3-y}
Dividing by 3-y undoes the multiplication by 3-y.
-xy+3y=8-3x
Subtract 3x from both sides.
\left(-x+3\right)y=8-3x
Combine all terms containing y.
\left(3-x\right)y=8-3x
The equation is in standard form.
\frac{\left(3-x\right)y}{3-x}=\frac{8-3x}{3-x}
Divide both sides by -x+3.
y=\frac{8-3x}{3-x}
Dividing by -x+3 undoes the multiplication by -x+3.
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Limits
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