Solve for a (complex solution)
\left\{\begin{matrix}a=\frac{3x+1}{y}\text{, }&y\neq 0\\a\in \mathrm{C}\text{, }&x=-\frac{1}{3}\text{ and }y=0\end{matrix}\right.
Solve for a
\left\{\begin{matrix}a=\frac{3x+1}{y}\text{, }&y\neq 0\\a\in \mathrm{R}\text{, }&x=-\frac{1}{3}\text{ and }y=0\end{matrix}\right.
Solve for x
x=\frac{ay-1}{3}
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-ay=-1-3x
Subtract 3x from both sides.
\left(-y\right)a=-3x-1
The equation is in standard form.
\frac{\left(-y\right)a}{-y}=\frac{-3x-1}{-y}
Divide both sides by -y.
a=\frac{-3x-1}{-y}
Dividing by -y undoes the multiplication by -y.
a=\frac{3x+1}{y}
Divide -3x-1 by -y.
-ay=-1-3x
Subtract 3x from both sides.
\left(-y\right)a=-3x-1
The equation is in standard form.
\frac{\left(-y\right)a}{-y}=\frac{-3x-1}{-y}
Divide both sides by -y.
a=\frac{-3x-1}{-y}
Dividing by -y undoes the multiplication by -y.
a=\frac{3x+1}{y}
Divide -1-3x by -y.
3x=-1+ay
Add ay to both sides.
3x=ay-1
The equation is in standard form.
\frac{3x}{3}=\frac{ay-1}{3}
Divide both sides by 3.
x=\frac{ay-1}{3}
Dividing by 3 undoes the multiplication by 3.
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