Solve for x
x=\frac{7y-4}{3}
Solve for y
y=\frac{3x+4}{7}
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3x=-4+7y
Add 7y to both sides.
3x=7y-4
The equation is in standard form.
\frac{3x}{3}=\frac{7y-4}{3}
Divide both sides by 3.
x=\frac{7y-4}{3}
Dividing by 3 undoes the multiplication by 3.
-7y=-4-3x
Subtract 3x from both sides.
-7y=-3x-4
The equation is in standard form.
\frac{-7y}{-7}=\frac{-3x-4}{-7}
Divide both sides by -7.
y=\frac{-3x-4}{-7}
Dividing by -7 undoes the multiplication by -7.
y=\frac{3x+4}{7}
Divide -4-3x by -7.
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